# Ex 7.7, 6 - Chapter 7 Class 12 Integrals (Term 2)

Last updated at Sept. 24, 2018 by Teachoo

Last updated at Sept. 24, 2018 by Teachoo

Transcript

Ex 7.7, 6 - Chapter 7 Class 12 Integrals - NCERT Integrate √(x^2 + 4x − 5) ∫√(x^2 + 4x − 5) dx = ∫√(x^2 + 2.2.x − 5) dx Adding and subtracting 2^2 = ∫√(x^2 + 2.2.x +(2)^2 - (2)^2 − 5) dx = ∫√((x + 2)^2 - 9) dx = ∫√((x + 2)^2 - 3^2) dx It is of the form ∫√x^2 - a^2 dx = x/2 √x^2 - a^2 - a^2/2 log |x + √x^2 - a^2| + C Replacing x by x + 2. a by 3 = (𝑥+2)/2 √(𝑥^2+4𝑥+4−9)−9/2 𝑙𝑜𝑔|𝑥+2+√(𝑥^2+4𝑥+4−9)|+𝐶 =(𝒙 + 𝟐)/𝟐 √(𝒙^𝟐+𝟒𝒙−𝟓)−𝟗/𝟐 𝒍𝒐𝒈|𝒙+𝟐+√(𝒙^𝟐+𝟒𝒙−𝟓)|+𝑪

Ex 7.7

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Ex 7.7, 6 You are here

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Ex 7.7, 12 (Supplementary NCERT) Important Deleted for CBSE Board 2022 Exams

Ex 7.7, 13 (Supplementary NCERT) Deleted for CBSE Board 2022 Exams

Ex 7.7, 14 (Supplementary NCERT) Important Deleted for CBSE Board 2022 Exams

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Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 10 years. He provides courses for Maths and Science at Teachoo.